8,000 miles is below the GEO altitude of 22,236 miles (was Deathstar Earth) Forum: Spacesettlers
Thread: 8,000 miles is below the GEO altitude of 22,236 miles (was Deathstar Earth)
# 12376 byvictors@... on March 24, 2012, 11:04 p.m.
Member since 2021-10-03
OK hitman, I know youre one of those guys that has to have it his way...Well call it micro-gravity, but as far as the Human organism is concerned, the subjective experience is weightlessness. Its like, if it feels like it, looks like it, behaves like it then for all intents and purposes it IS it. Centrifugal force is not gravity either, but in big ONeil habitat itll sure as hell feel, look and behave like it. So whats your beef with weightlessness?
Sent: Saturday, March 24, 2012 11:05 AM
To: spacesettlers@yahoogroups.com
Subject: [spacesettlers] 8,000 miles is below the GEO altitude of 22,236 miles (was Re: Deathstar Earth)
--- In mailto:spacesettlers%40yahoogroups.com, "Victor Smith" wrote:
> People near the top damn well better turn around, or their gonna fall on their heads, because, just like inside any spinning huge torus, the outside bulkhead becomes the floor by centrifugal force
No, because 8,000 miles is below the GEO altitude of 22,236 miles:
http://en.wikipedia.org/wiki/Geosynchronous_orbit
"A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level."
> I suspect that you would find a region somewhere between the roof and the basement where gravity and centrifugal force cancel each other out and you reach a state of equilibrium- for all intent and purposes, weightless
No, because 8,000 miles is below the GEO altitude of 22,236 miles:
http://en.wikipedia.org/wiki/Geosynchronous_orbit
"A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level."
> but I'm not mathematician enough to figure where.
You don't need to figure out where. Scientists figured it out *for* you:
http://en.wikipedia.org/wiki/Geosynchronous_orbit
"A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level."
> > > are we all going to fly at the higher elevations, 'cause we ought to be weightless.
> > No, because even at the highest elevations, you won't be at GEO.
> Well, folks float in LEO
That's because people in LEO have an orbital period that's less than the one we're taking about: one sidereal day (approximately 23 hours 56 minutes and 4 seconds), matching the Earth's sidereal rotation period.
> and on the vomit comet
The vomit comet flies parabolas. People only float in the vomit comet when it's descending.
> As I conjectured above, at some point between the current ground level and the "Roof of the World", 8,000 miles up, there will be a point where the centrifugal force pressing you outward and the force of Gravity, pulling you groundward will be completely equal
No, because 8,000 miles is below the GEO altitude of 22,236 miles:
http://en.wikipedia.org/wiki/Geosynchronous_orbit
"A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level."
> and at that level you should experience weightlessness.
No, because 8,000 miles is below the GEO altitude of 22,236 miles:
http://en.wikipedia.org/wiki/Geosynchronous_orbit
"A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level."
> above that point, centrifugal force will grow so you better flip over and start using the roof as a floor.
No, because 8,000 miles is below the GEO altitude of 22,236 miles:
http://en.wikipedia.org/wiki/Geosynchronous_orbit
"A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level."